目錄
正文
用戶名,月份,訪問次數
A,2015-01,5A,2015-01,15B,2015-01,5A,2015-01,8B,2015-01,25A,2015-01,5A,2015-02,4A,2015-02,6B,2015-02,10B,2015-02,5A,2015-03,16A,2015-03,22B,2015-03,23B,2015-03,10B,2015-03,1
use myhive;create external table if not exists t_access(uname string comment '用戶名',umonth string comment '月份',ucount int comment '訪問次數') comment '用戶訪問表' row format delimited fields terminated by "," location "/hive/t_access";
load data local inpath "/home/hadoop/access.txt" into table t_access;
select * from t_access;
現要求出:
每個用戶截止到每月為止的最大單月訪問次數和累計到該月的總訪問次數,結果數據格式如下
此結果需要根據用戶+月份進行分組
--求當月訪問次數create table tmp_access(name string,mon string,num int); insert into table tmp_access select uname,umonth,sum(ucount) from t_access t group by t.uname,t.umonth;
select * from tmp_access;
create view tmp_view as select a.name anme,a.mon amon,a.num anum,b.name bname,b.mon bmon,b.num bnum from tmp_access a join tmp_access b on a.name=b.name;select * from tmp_view;
select anme,amon,anum,max(bnum) as max_access,sum(bnum) as sum_access from tmp_view where amon>=bmon group by anme,amon,anum;
// 插入數據// 字段解釋:id, 學號, 課程, 成績INSERT INTO `course` VALUES (1, 1, 'yuwen', 43);INSERT INTO `course` VALUES (2, 1, 'shuxue', 55);INSERT INTO `course` VALUES (3, 2, 'yuwen', 77);INSERT INTO `course` VALUES (4, 2, 'shuxue', 88);INSERT INTO `course` VALUES (5, 3, 'yuwen', 98);INSERT INTO `course` VALUES (6, 3, 'shuxue', 65);
求:所有數學課程成績 大于 語文課程成績的學生的學號
create view tmp_course_view asselect sid, case course when "shuxue" then score else 0 end as shuxue, case course when "yuwen" then score else 0 end as yuwen from course; select * from tmp_course_view;
create view tmp_course_view1 asselect aa.sid, max(aa.shuxue) as shuxue, max(aa.yuwen) as yuwen from tmp_course_view aa group by sid; select * from tmp_course_view1;
select * from tmp_course_view1 where shuxue > yuwen;
數據格式
2010012325
具體數據
數據解釋
2010012325表示在2010年01月23日的氣溫為25度
比如:2010012325表示在2010年01月23日的氣溫為25度。現在要求使用hive,計算每一年出現過的最大氣溫的日期+溫度。
要計算出每一年的最大氣溫。我用
select substr(data,1,4),max(substr(data,9,2)) from table2 group by substr(data,1,4);
出來的是 年份 + 溫度 這兩列數據例如 2015 99
但是如果我是想select 的是:具體每一年最大氣溫的那一天 + 溫度 。例如 20150109 99
請問該怎么執行hive語句。。
group by 只需要substr(data,1,4),
但是select substr(data,1,8),又不在group by 的范圍內。
是我陷入了思維死角。一直想不出所以然。。求大神指點一下。
在select 如果所需要的。不在group by的條件里。這種情況如何去分析?
create table tmp_weather as select substr(data,1,4) years,substr(data,5,2) months,substr(data,7,2) days,substr(data,9,2) temp from weather;
select * from tmp_weather;
create table tmp_year_weather as select substr(data,1,4) years,max(substr(data,9,2)) max_temp from weather group by substr(data,1,4);
select * from tmp_year_weather;
select * from tmp_year_weather a join tmp_weather b on a.years=b.years and a.max_temp=b.temp;
表示有id為1,2,3的學生選修了課程a,b,c,d,e,f中其中幾門。
create table t_course(id int,course string)row format delimited fields terminated by ",";
load data local inpath "/home/hadoop/course/course.txt" into table t_course;
編寫Hive的HQL語句來實現以下結果:表中的1表示選修,表中的0表示未選修
id a b c d e f1 1 1 1 0 1 02 1 0 1 1 0 13 1 1 1 0 1 0
第一步:
select collect_set(course) as courses from id_course;
第二步:
set hive.strict.checks.cartesian.product=false;create table id_courses as select t1.id as id,t1.course as id_courses,t2.course courses from ( select id as id,collect_set(course) as course from id_course group by id ) t1 join (select collect_set(course) as course from id_course) t2;
啟用嚴格模式:hive.mapred.mode = strict // Deprecated
hive.strict.checks.large.query = true
該設置會禁用:1. 不指定分頁的orderby
2. 對分區表不指定分區進行查詢
3. 和數據量無關,只是一個查詢模式hive.strict.checks.type.safety = true
嚴格類型安全,該屬性不允許以下操作:1. bigint和string之間的比較
2. bigint和double之間的比較hive.strict.checks.cartesian.product = true
該屬性不允許笛卡爾積操作
第三步:得出最終結果:
思路:
拿出course字段中的每一個元素在id_courses中進行判斷,看是否存在。
select id,case when array_contains(id_courses, courses[0]) then 1 else 0 end as a,case when array_contains(id_courses, courses[1]) then 1 else 0 end as b,case when array_contains(id_courses, courses[2]) then 1 else 0 end as c,case when array_contains(id_courses, courses[3]) then 1 else 0 end as d,case when array_contains(id_courses, courses[4]) then 1 else 0 end as e,case when array_contains(id_courses, courses[5]) then 1 else 0 end as f from id_courses;
a,01,150a,01,200b,01,1000b,01,800c,01,250c,01,220b,01,6000a,02,2000a,02,3000b,02,1000b,02,1500c,02,350c,02,280a,03,350a,03,250
店鋪,月份,金額
use class;create table t_store(name string,months int,money int) row format delimited fields terminated by ",";
load data local inpath "/home/hadoop/store.txt" into table t_store;
編寫Hive的HQL語句求出每個店鋪的當月銷售額和累計到當月的總銷售額
(1)按照商店名稱和月份進行分組統計
create table tmp_store1 as select name,months,sum(money) as money from t_store group by name,months;select * from tmp_store1;
(2)對tmp_store1 表里面的數據進行自連接
create table tmp_store2 as select a.name aname,a.months amonths,a.money amoney,b.name bname,b.months bmonths,b.money bmoney from tmp_store1 a join tmp_store1 b on a.name=b.name order by aname,amonths;select * from tmp_store2;
(3)比較統計
select aname,amonths,amoney,sum(bmoney) as total from tmp_store2 where amonths >= bmonths group by aname,amonths,amoney;